Math 1600 Section 1.2 Question 66
$
\newcommand{\bmat}[1]{\left[\begin{array}{#1}}
\newcommand{\emat}{\end{array}\right]}
\newcommand{\coll}[2]{\bmat{r} #1 \\ #2 \emat}
\newcommand{\colll}[3]{\bmat{r} #1 \\ #2 \\ #3 \emat}
\newcommand{\red}[1]{{\color{red}#1}}
\newcommand{\lra}[1]{\mbox{$\xrightarrow{#1}$}}
\newcommand{\rank}{\textrm{rank}}
\newcommand{\mystack}[2]{\genfrac{}{}{0}{0}{#1}{#2}}
\newcommand{\mystackthree}[3]{\mystack{\mystack{#1}{#2}}{#3}}
\newcommand{\query}[1]{\toggle{\text{?}\vphantom{#1}}{#1}\endtoggle}
$
The answer is exercise 66 in section 1.2 is $\query{3}$ (click to reveal).
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